# Line slope calculator 4x-3y=-8

**Straight line given by points A[1; 4] and B[4; 8]**

## Calculation:

**Slope-intercept form of line:**y = 1.3333x+2.6667

**Canonical form of the line equation:**4x-3y+8 = 0

**Parametric form of the line equation:**

x = 3t+1

y = 4t+4 ; t ∈ R

**Slope:**m = 1.3333

**Slope angle of line: φ =**53°7'48″ = 0.9273 rad

**X intercept:**x

_{0}= -2

**Y intercept:**y

_{0}= q = 2.6667

**Distance line from the origin:**d

_{0}= 1.6

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; 4)

**Normal vector: n =**(4; -3)

**Midpoint of the segment AB: M =**[2.5; 6]

**Perpendicular Bisector equation:**3x+4y-31.5 = 0

**Vector OA = (1; 4) ; |OA| = 4.1231**

**Vector OB = (4; 8) ; |OB| = 8.9443**

**Scalar product OA .OB = 36**

**Angle ∠ AOB = 12°31'44″ = 0.2187 rad**