# Line slope calculator 2x-5y=-16

**Straight line given by points A[2; 4] and B[7; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.4x+3.2

**Canonical form of the line equation:**2x-5y+16 = 0

**Parametric form of the line equation:**

x = 5t+2

y = 2t+4 ; t ∈ R

**Slope:**m = 0.4

**Slope angle of line: φ =**21°48'5″ = 0.3805 rad

**X intercept:**x

_{0}= -8

**Y intercept:**y

_{0}= q = 3.2

**Distance line from the origin:**d

_{0}= 2.9711

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; 2)

**Normal vector: n =**(2; -5)

**Midpoint of the segment AB: M =**[4.5; 5]

**Perpendicular Bisector equation:**5x+2y-32.5 = 0

**Vector OA = (2; 4) ; |OA| = 4.4721**

**Vector OB = (7; 6) ; |OB| = 9.2195**

**Scalar product OA .OB = 38**

**Angle ∠ AOB = 22°50'1″ = 0.3985 rad**